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11n^2-11n+2=0
a = 11; b = -11; c = +2;
Δ = b2-4ac
Δ = -112-4·11·2
Δ = 33
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-\sqrt{33}}{2*11}=\frac{11-\sqrt{33}}{22} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+\sqrt{33}}{2*11}=\frac{11+\sqrt{33}}{22} $
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